ZCGESV - Online Linux Manual PageSection : 1
Updated : November 2008
Source : LAPACK PROTOTYPE driver routine (version 3.2)
Note : LAPACK PROTOTYPE driver routine (version 3.2)

NAMEZCGESV - computes the solution to a complex system of linear equations A * X = B,

SYNOPSISSUBROUTINE ZCGESV(  N, NRHS, A, LDA, IPIV, B, LDB, X, LDX, WORK,  + SWORK, RWORK, ITER, INFO )  INTEGER INFO, ITER, LDA, LDB, LDX, N, NRHS  INTEGER IPIV( * )  DOUBLE PRECISION RWORK( * )  COMPLEX SWORK( * )  COMPLEX*16 A( LDA, * ), B( LDB, * ), WORK( N, * ),  + X( LDX, * )

PURPOSEZCGESV computes the solution to a complex system of linear equations
   A * X = B, where A is an N-by-N matrix and X and B are N-by-NRHS matrices. ZCGESV first attempts to factorize the matrix in COMPLEX and use this factorization within an iterative refinement procedure to produce a solution with COMPLEX*16 normwise backward error quality (see below). If the approach fails the method switches to a COMPLEX*16 factorization and solve.
The iterative refinement is not going to be a winning strategy if the ratio COMPLEX performance over COMPLEX*16 performance is too small. A reasonable strategy should take the number of right-hand sides and the size of the matrix into account. This might be done with a call to ILAENV in the future. Up to now, we always try iterative refinement.
The iterative refinement process is stopped if

    ITER > ITERMAX
or for all the RHS we have:

    RNRM < SQRT(N)*XNRM*ANRM*EPS*BWDMAX
where

    o ITER is the number of the current iteration in the iterative
      refinement process

    o RNRM is the infinity-norm of the residual

    o XNRM is the infinity-norm of the solution

    o ANRM is the infinity-operator-norm of the matrix A

    o EPS is the machine epsilon returned by DLAMCH('Epsilon') The value ITERMAX and BWDMAX are fixed to 30 and 1.0D+00
respectively.

ARGUMENTSN (input) INTEGER  The number of linear equations, i.e., the order of the matrix A. N >= 0. NRHS (input) INTEGER  The number of right hand sides, i.e., the number of columns of the matrix B. NRHS >= 0. A (input or input/ouptut) COMPLEX*16 array,  dimension (LDA,N) On entry, the N-by-N coefficient matrix A. On exit, if iterative refinement has been successfully used (INFO.EQ.0 and ITER.GE.0, see description below), then A is unchanged, if double precision factorization has been used (INFO.EQ.0 and ITER.LT.0, see description below), then the array A contains the factors L and U from the factorization A = P*L*U; the unit diagonal elements of L are not stored. LDA (input) INTEGER  The leading dimension of the array A. LDA >= max(1,N). IPIV (output) INTEGER array, dimension (N)  The pivot indices that define the permutation matrix P; row i of the matrix was interchanged with row IPIV(i). Corresponds either to the single precision factorization (if INFO.EQ.0 and ITER.GE.0) or the double precision factorization (if INFO.EQ.0 and ITER.LT.0). B (input) COMPLEX*16 array, dimension (LDB,NRHS)  The N-by-NRHS right hand side matrix B. LDB (input) INTEGER  The leading dimension of the array B. LDB >= max(1,N). X (output) COMPLEX*16 array, dimension (LDX,NRHS)  If INFO = 0, the N-by-NRHS solution matrix X. LDX (input) INTEGER  The leading dimension of the array X. LDX >= max(1,N). WORK (workspace) COMPLEX*16 array, dimension (N*NRHS)  This array is used to hold the residual vectors. SWORK (workspace) COMPLEX array, dimension (N*(N+NRHS))  This array is used to use the single precision matrix and the right-hand sides or solutions in single precision. RWORK (workspace) DOUBLE PRECISION array, dimension (N)  ITER (output) INTEGER  < 0: iterative refinement has failed, COMPLEX*16 factorization has been performed -1 : the routine fell back to full precision for implementation- or machine-specific reasons -2 : narrowing the precision induced an overflow, the routine fell back to full precision -3 : failure of CGETRF
-31: stop the iterative refinement after the 30th iterations > 0: iterative refinement has been sucessfully used. Returns the number of iterations
INFO (output) INTEGER  = 0: successful exit
< 0: if INFO = -i, the i-th argument had an illegal value
> 0: if INFO = i, U(i,i) computed in COMPLEX*16 is exactly zero. The factorization has been completed, but the factor U is exactly singular, so the solution could not be computed. =========
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